Nettetput :integration by parts of Int [ sin (ln (x))dx]u = sin (lnx)du = (1/x)cos (lnx)dxdv = dxv = x Int [ sin (ln (x))dx] … View the full answer Transcribed image text: Evaluate the integral: sin (lnx)d x Previous question Next question Get more help from Chegg Solve it with our Calculus problem solver and calculator. Nettet20. des. 2024 · Exponential functions can be integrated using the following formulas. ∫exdx = ex + C ∫axdx = ax lna + C Example 5.6.1: Finding an Antiderivative of an Exponential Function Find the antiderivative of the exponential function e − x. Solution Use substitution, setting u = − x, and then du = − 1dx.
Quora - A place to share knowledge and better understand the …
Nettet7. aug. 2024 · Calculus Techniques of Integration Integration by Parts 1 Answer maganbhai P. Aug 7, 2024 ∫sin(lnx)dx = x 2 [sin(lnx) −cos(lnx)] + C Explanation: Here, I = ∫sin(lnx)dx.................(A) Subst. lnx = u ⇒ x = eu ⇒ dx = eudu ∴ I = ∫sinu ⋅ eudu Using Integration by parts: I = sinu∫eudu −∫( d du (sinu)∫eudu)du ∴ I = sinu ×eu − ∫cosueudu NettetIntegral of x*sin(ln(x)) - How to integrate it by parts step by step!👋 Follow @integralsforyou on Instagram for a daily integral 😉📸 @integralsforyou https... hate bazare express 13163 live status
calculus - Evaluate Integral of $\sin(\ln(x))dx$ - Mathematics Stack ...
Nettet23. feb. 2016 · Integrating by parts: u = sin (t), du = cos (t) dt dv = e t dt, v = e t 5 (sin (t)e t - ∫cos (t)e t dt) By parts again: u=cos (t), du=-sin (t) dt dv = e t dt, v = e t 5 [sin (t)e t - (cos (t)e t + ∫sin (t)e t dt)] Distributing the 5 and the negative sign: 5∫sin (t)e t dt = 5sin (t)e t - 5cos (t)e t - 5∫sin (t)e t dt] NettetIntegrate 7sin(lnx)dx; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See … bootrec parameter