Web5 boys and 5 girls sit in a row at random. The probability that the boys and girls an alternatively is A 145 B 283 C 1261 D 111 Medium Solution Verified by Toppr Correct option is C) 5 boys and 5 girls sit in a row at random ∴ No of ways they can sit =(5+5)! =10! ∴ No of ways that the boys and girls sit alternatively =51×5!×2 WebFive boys and three girls are seated at random in a row. Find the probability that no boy sits between two girls. Solution.: n ( s) = 8! n (E) = The number of arrangement of 5 boys and 3 girls when 3 girls are consecutive = 6! × 3! …

Five girls are sitting in a row Jane is not adjacent to Mary or ria ...

WebQ. 6 girls and 5 boys sit together randomly in a row, the probability that no two boys sit together, is Q. Six boys and girls sit in a row randomly. Find the probability that t he boys and girls sit alternately. WebThe number of permutation of these 5 girls is 5! = 120 \color{#4257b2}{5!=120} 5! = 120. So these 5 girls can be arranged among themselfs in 120 … fish tank buildup

5 boys and 4 girls sit in a straight line. Find the number of ways in ...

Web1. Five girls are sitting on a bench for a photograph. 2. Seema is to the left of Rani and to the right of Bindu. 3. Mary is to the right of Rani. 4. Reeta is between Rani and Mary. The … WebQuestion 5 boys & 3 girls are sitting in a row of 8 seats. Number of ways in which they can be seated so that not all the girls sit side by side, is? A 36000 B 9080 C 3960 D 11600 Medium Solution Verified by Toppr Correct option is A) Total no of ways they can be arranged is without any restrictions = 8! ways. WebMar 14, 2015 · Given a particular seating arrangement of the girls, say Anne, Beth, Carol, and Dalia, the four rotations (Anne, Beth, Carol, Dalia), (Beth, Carol, Dalia, Anne), (Carol, Dalia, Anne, Beth), and (Dalia, Anne, Beth, Carol) leave the girls in the same relative order, so you must divide your answer by 4. – N. F. Taussig Mar 13, 2015 at 23:55 fish tank bulb